How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
The radius of a sphere is 3 cm. Find, in terms of π, its volume.
\(30\pi cm^3\)
\(108\pi cm^3\)
\(27\pi cm^3\)
\(36\pi cm^3\)
Correct answer is D
Given that radius = 3cm.
volume of sphere = \(\frac{4}{3}\times\pi\times r^3\)
= \(\frac{4}{3}\times\pi\times 3^3\)
= \(\frac{4}{3}\times\pi\times 27\)
= \(4\times\pi\times9\)
= \(36\pi cm^3\)
\(1,106.29cm^2\)
\(1,016.29cm^2\)
\(1,106.89cm^2\)
\(1,206.27cm^2\)
Correct answer is A
radius = 8cm , height = 14cm and \(\pi = \frac{22}{7}\)
total surface area of a solid cylinder =\( 2πrh+2πr^2\) = 2πr( h + r )
\( 2 \times \frac{22}{7} \times 8( 8 + 14)\)
\( 2 \times \frac{22}{7} \times 8 \times 22\)
\(\frac{7744}{7}\)
= \(1,106.29cm^2\)
6.29m
7.67m
7.18m
6.65m
Correct answer is A
%error=5%, measured height = 5.98m
let the actual height = y
error=x - 5.98 (since 'y' is more than 5.98)
%error = \(\frac{error}{actual height}\times 100%\)
5% = \(\frac{y - 5.98}{y}\times 100%\)
\(\frac{5}{100} = \frac{y - 5.98}{y}\)
5y = 100(y - 5.98)
5y = 100y - 598
5y - 100y = - 598
-95y = - 598
y = \(\frac{-598}{-95}\)
y = 6.29m( to 2 d.p).
Find the roots of the equations: \(3m^2 - 2m - 65 = 0\)
\(( -5, \frac{-13}{3})\)
\(( 5, \frac{-13}{3})\)
\(( 5, \frac{13}{3})\)
\(( -5, \frac{13}{3})\)
Correct answer is B
Find the roots of the equations: \(3m^2 - 2m - 65 = 0\)
= \( m^2 - 15m + 13m - 65 = 0\)
= 3m(m - 5) + 13( m - 5) = 0
( m - 5)(3m + 13) = 0
m-5 = 0 or 3m + 13 = 0
therefore, m = 5 or \(\frac{-13}{3}\)
therefore the roots of the quadratic equation = ( 5, \(\frac{-13}{3})\)
If \(log_a 3\) = m and \(log_a 5\) = p, find \(log_a 75\)
\(m^2 + p \)
2m + p
m + 2p
\(m + p^2\)
Correct answer is C
Given: \(log_a 3\) = m and \(log_a 5\) = p
\(log_a 75\) = \(log_a (3 × 25)\)
= \(log_a (3 × 5^2)\)
= \(log_a 3 + log_a 5^2\)
= \(log_a 3 + 2log_a 5\)
Since \(log_a 3\) = m and \(log_a 5\) = p
∴ \(log_a 75\) = m + 2p
Solve \(2^{5x} \div 2^x = \sqrt[5]{2^{10}}\)
\(\frac{3}{2}\)
\(\frac{1}{2}\)
\(\frac{1}{3}\)
\(\frac{5}{3}\)
Correct answer is B
\(2^{5x} \div 2^x = \sqrt[5]{2^{10}}\)
applying the laws of indices
\(2^{5x - x} = 2^{10(1/5)}\)
\(2^{4x} = 2^{10(1/5)}\)
\(2^{4x} = 2^2\)
Equating the powers
then 4x = 2
therefore, x = \(\frac{2}{4}\) = \(\frac{1}{2}\)
12
15
10
14
Correct answer is D
each interior angle of a polygon = \(\frac{(n - 2)\times 180}{n}\) where n = no of side of a polygon
each exterior angle of a polygon = \(\frac{360}{n}\)
then \(\frac{(n - 2)\times 180}{n}\) = 6\(\times\) \(\frac{360}{n}\)
= (n - 2) 180 = 2160
= 180n - 360 = 2160
= 180n = 2160 + 360
= 180n = 2520
therefore, n = \(\frac{2520}{180}\) = 14.
Evaluate, correct to three decimal place \(\frac{4.314 × 0.000056}{0.0067}\)
0.037
0.004
0.361
0.036
Correct answer is D
\(\frac{4.314 × 0.000056}{0.0067}\)
\(\frac{0.000242}{0.0067}\)
= 0.036 ( to 3 decimal places)
\(2311_5\)
\(1131_5\)
\(1311_5\)
\(2132_5\)
Correct answer is C
\(413_7\) to base 5
convert first to base 10
\(417_7 = 4 × 7^2 + 1 × 7^1 + 3 × 7^0\)
= 4 × 49 + 1 × 7 + 3 × 1
= 196 + 7 + 3
= \(206_{10}\)
convert this result to base 5
5 | 206 |
5 | 41R1 |
5 | 8R1 |
5 | 1R3 |
0R1 |
\(∴ 413_7 = 1311_5\)
For what value of x is \(\frac{ x^2 + 2 }{ 10x^2 - 13x - 3}\) is undefined?
\(\frac{1}{5}, \frac{3}{2}\)
\(\frac{-1}{5}, \frac{3}{2}\)
\(\frac{1}{5}, \frac{-3}{2}\)
\(\frac{-1}{5}, \frac{-3}{2}\)
Correct answer is B
The fraction \(\frac{ x^2 + 2 }{ 10x^2 - 13x - 3}\) is undefined when the denominator is equal to zero
\(then 10x^2 - 13x - 3 = 0\)
by factorisation, \(10x^2 - 13x - 3\) = 0 becomes \( 10x^2 - 15x +2x -3\) = 0
\(5x(2x - 3) + 1(2x - 3) = 0\)
\((5x + 1)(2x - 3) = 0\)
\(then, x = \frac{-1}{5}\) or \(\frac{3}{2}\)
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