0.3oC
3.0oC
33.3oC
42.0oC
100.0oC
Correct answer is B
\(\Delta t = \frac{gh}{c} = \frac{1260 \times 10}{4200}\)
= 3.0°
360.0oC
240.6oC
237.0oC
87.0oC
36oC
Correct answer is D
T1 = \(\frac{V_1T_2}{V_2} = \frac{60 \times (273 + 27)}{50}\)
= 360k
= 360 - 273
= 87.0oC
1.5 atmospheres
2.5 atmospheres
3.0 atmospheres
12.8 atmospheres
15.0 atmospheres
Correct answer is C
\(\frac{V_1P_1}{T_1} = \frac{V_2P_2}{T_2}\)
\(\frac{1 \times 30}{527 + 2733} = \frac{5P_2}{127 + 273}\)
\(\frac{30}{800} = \frac{5p_2}{400}\)
P2 = \(\frac{400 \times 30}{800 \times 5}\)
= 3
2.85 x 10-5K-1
1.90 x 10-5K-1
1.86 x 10-5K-1
1.70 x 10-5K-1
1.63 x 10-5K-1
Correct answer is B
\(\alpha\) = \(\frac{\Delta}{3} = \frac{5.7 \times 10^{-5}}{3}\)
= 1.90 x 10-5K-1
The average kinetic energy of the molecules of a perfect gas is directly proportional to the
pressure exerted by the gas
volume of the gas molecule
kelvin temperature of the gas
volume of the gas container
celcius temperature of the gas
Correct answer is C
The average kinetic energy of the molecules of a perfect gas is directly proportional to the Absolute temperature that is the temperature measured using the kelvin scale.