-5
-3
−12
5
Correct answer is A
Let f(x)=y, then we have
y=x+12⟹2y=x+1;x=2y−1
Let f1(x)=x;x=2y−1, replacing y with x,
f1(x)=2x−1⟹f1(−2)=2(−2)−1=−5
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