Numerical Reasoning Questions and Answers

No. of digits in 1-digit page nos. = 1x9 = 9.

No. of digits in 2-digit page nos. = 2 x 90 = 180.

No. of digits in 3-digit page nos. = 3 x 900 = 2700.

No. of digits in 4-digit page nos. = 3189 - (9 + 180 + 2700) = 3189 - 2889 = 300.

Therefore No. of pages with 4-digit page nos. = (300/4) = 75.

Hence, total number of pages = (999 + 75) = 1074.

Since the number of carbons is 2, only two copies can be obtained.

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Clearly, we have to first find two numbers whose difference is 2 and of which the smaller one is a perfect square and the bigger one a perfect cube.

Such numbers are 25 and 27.

Thus, Edet is now 26 years old. Since the next perfect cube after 27 is 64,

so required time period = (64 - 26) years = 38 years.

Income on the first day = $1

Income on the 2nd day = $(1x2) = $2¹

Income on the 3rd day = $(2¹ x 2) = $2² and so on. Thus, Income on the nth day = $2^n-1.

Therefore Income on the 10th day = $2⁹.

Let the ten's digit be x. Then, unit's digit = (11 - x).

So, number = 10x + (11 - x) = 9x + 11.

Therefore (9x + 11) + 27 = 10 (11 - x) + x ⇔ 9x + 38 = 110 - 9x ⇔ 18x = 72 ⇔ x = 4.

Thus, ten's digit = 4 and unit's digit = 7.

Hence, required number = 47.

Net ascent of the monkey in 1 hour = (30 - 20) feet = 10 feet.

So, the monkey ascends 90 feet in 9 hours i.e. till 5 p.m.

Clearly, in the next 1 hour i.e. till 6 p.m. the monkey ascends remaining 30 feet to touch the flag.

Let number of keepers be x. Then,

Total number of feet = 2 x 50 + 4 x 45 + 4 x 8 + 2x = 2x + 312.

Total number of heads = 50 + 45 + 8 + x= 103 + x.

Therefore (2x + 312) = (103 + x) + 224 or x = 15.

Clearly, out of every 16 persons, there is one captain. So, number of captains (1200/16) = 75.

Let the total number of sweets be (25x + 8).

Then, (25x + 8) - 22 is divisible by 28

⇔ (25x - 14) is divisible by 28 ⇔ 28x - (3x + 14) is divisible by 28

⇔ (3x + 14) is divisible by 28 ⇔ x = 14.

Therefore Total number of sweets = (25 x 14 + 8) = 358.