A straight line 2x+3y=6, passes through the point (-1,2)....
A straight line 2x+3y=6, passes through the point (-1,2). Find the equation of the line.
2x-3y=2
2x-3y=-2
2x+3y=-4
2x+3y=4
Correct answer is D
2x+3y=6⟹3y=6−2x
y=63−2x3
Parallel lines have the same gradient
∴ Gradient of the line = \frac{-2}{3}
Line passes through (-1,2)
Equation: \frac{y-2}{x-(-1)} = \frac{y-2}{x+1} = \frac{-2}{3}
3y-6 = -2x-2 \implies 3y+2x = -2+6 =4
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