A=(−3−512)
A=(3−512)
A=(3−5−12)
A=(−351−2)
Correct answer is C
B.B−1=1, let B−1=(abcd)
(2513)(abcd) = (1001)
Multiplying B×B−1, we have the following equations:
2a+5c=1.........(1); a+3c=0........(2)
2b+5d=0..........(3); b+3d=1..........(4)
Solving the equations simultaneously, we have
a=3;b=−5;c=−1;d=2⟹B−1=(3−5−12)
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