\(a = b^{3} - 3\)
\(a = b^{3} - 9\)
\(a = 9b^{3}\)
\(a = \frac{b^{3}}{9}\)
Correct answer is C
\(\log_{3}a - 2 = 3\log_{3}b\)
Using the laws of logarithm, we know that \( 2 = 2\log_{3}3 = \log_{3}3^{2}\)
\(\therefore \log_{3}a - \log_{3}3^{2} = \log_{3}b^{3}\)
= \(\log_{3}(\frac{a}{3^{2}}) = \log_{3}b^{3} \implies \frac{a}{9} = b^{3}\)
\(\implies a = 9b^{3}\)
If V = plog\(_x\), (M + N), express N in terms of X, P, M and V...
If →PQ = -2i + 5j and →RQ = -i - 7j, find →PR ...
Solve the inequality \(2x^{2} + 5x - 3 \geq 0\)....
Marks 5 - 7 8 - 10 11 - 13 14 - 16 17 - 19 20 - 22 Frequency 4 7 26 41 1...
If α and β are the roots of 3x\(^2\) - 7x + 6 = 0, find \(\frac{1}{α}\) +...
In how many ways can six persons be paired? ...
Given that f: x --> x\(^2\) - x + 1 is defined on the Set Q = { x : 0 ≤ x < 20, x...
Given that 2x + 3y - 10 and 3x = 2y - 11, calculate the value of (x - y). ...
Marks 2 3 4 5 6 7 8 No of students 5 7 9 6 3 6 4 The table above sho...