a=b3−3
a=b3−9
a=9b3
a=b39
Correct answer is C
log3a−2=3log3b
Using the laws of logarithm, we know that 2=2log33=log332
∴
= \log_{3}(\frac{a}{3^{2}}) = \log_{3}b^{3} \implies \frac{a}{9} = b^{3}
\implies a = 9b^{3}
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