(−8−532)
(−8−53−2)
(−8−5−32)
(−8−5−3−2)
Correct answer is A
Let (abcd)=T−1
T.T−1=I
(−2−538)(abcd)=(1001)
⟹−2a−5c=1
−2b−5d=0⟹b=−5d2
3a+8c=0⟹a=−8c3
3b+8d=1
−2(−8c3)−5c=16c3−5c=c3=1⟹c=3
3(−5d2)+8d=−15d2+8d=d2=1⟹d=2
b=−5×22=−5
a=−8×33=−8
∴
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