11.6 N
11.7 N
11.8 N
11.9 N
Correct answer is B
F = F \cos \theta i + F \sin \theta j (Resolving F into its components)
F_{1} = (10 N, 090°) = 10 \cos 90 i + 10 \sin 90 j
= 10 j
F_{2} = (6 N, 180°) = 6 \cos 180 i + 6 \sin 180 j
= -6 i
R = - 6 i + 10 j
|R| = \sqrt{(-6)^{2} + (10)^{2}}
= \sqrt{136}
= 11.7 N
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