f(x)=x3−3x2+x+20
f(x)=x3−3x2+x+31
f(x)=x3−3x2+x+2
f(x)=x3−3x2+x−13
Correct answer is C
f′(x)=3x2−6x+1
f(x)=∫(3x2−6x+1)dx
= x3−3x2+x+c
f(3)=5=33−3(32)+3+c
27−27+3+c=5⟹3+c=5
c=2
f(x)=x3−3x2+x+2
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