3,(−1,2)
2√2,(2,−1)
2√2,(2,1)
9,(2,1)
Correct answer is C
Equation of a circle with radius r and centre (a, b).
= (x−a)2+(y−b)2=r2
Expanding, we have
x2−2ax+a2+y2−2by+b2=r2
Comparing, with x2+y2−4x−2y−3=0
2a=4⟹a=2
2b=2⟹b=1
r2−a2−b2=3⟹r2=3+22+12=8
r=2√2
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