19 ms−2
21 ms−2
41 ms−2
31 ms−2
Correct answer is C
S=5t3−192t2+6t−4
v(t)=dSdt=15t2−19t+6
a(t)=dvdt=30t−19
∴a(2)=30(2)-19=60-19=41 ms−2
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