What is log7(49a) - log10(0.01)?
\(\frac{49^a}{100}\)
\(\frac{a}{2}\) + 2
72a + 2
2a + 2
\(\frac{2a}{2}\)
Correct answer is D
log7(49a) - log10(0.01) = log7(72)a - log10100
log772a - log101 - log10 102
= 2a - 2
= 2a + a
\(\sqrt{2239cm}\)
\(\sqrt{2}\) x 2239cm
\(\frac{\sqrt{3}}{2}\) 2239cm
\(\sqrt{3}\) x 2239cm
4478cm
Correct answer is D
x = \(\sqrt{-2239^2 + 2239^2}\)
= -\(\sqrt{10026242}\)
= 3166.42
y = -\(\sqrt{10026242 + 5013121}\)
= -\(\sqrt{15039363}\)
= 3878
= \(\sqrt{3}\) x 2239
An arc of circle of radius 2cm subtends an angle of 60º at the centre. Find the area of the sector
\(\frac{2 \pi}{3}\)cm2
\(\frac{\pi}{2}\)cm2
\(\frac{\pi}{3}\)cm2
\(\pi\)cm2
Correct answer is A
Area of a sector \(\frac{\theta}{360}\) x \(\pi\)r\(^2\)
= \(\frac{60^o}{360^o}\) x \(\pi\)2\(^2\)
= \(\frac{2 \pi}{3}\)cm2
A cylinder of height h and radius r is open at one end. Its surface area is
2\(\pi\)rh
\(\pi\)r2h
2\(\pi\)rh + \(\pi\)r2
2\(\pi\)rh + 2\(\pi\)r2
Correct answer is C
A cylinder of height h ans radius r is open at one end, its surface area is 2\(\pi\)rh + \(\pi\)r2
Simplify \(\frac{1 - x^2}{x - x^2}\), where x \(\neq\) 0
\(\frac{1}{x}\)
\(\frac{1 - x}{x}\)
\(\frac{1 + x}{x}\)
\(\frac{1}{x - 1}\)
\(\frac{-x - 1}{1}\)
Correct answer is C
\(\frac{1 - x^2}{x - x^2}\), where x = \(\neq\) 0
\(\frac{1^2 - x^2}{x - x^2}\)
= \(\frac{(1 + x)(1 - x)}{x(1 - x)}\)
= \(\frac{1 + x}{x}\)