Water shows anomalous behaviour.
below 0oC
between 0oC and 4oC
at exactly 4oC
between 4oC and 100oC
above 100oC
Correct answer is B
No explanation has been provided for this answer.
force
force/m
work
force/m3
energy/m3
Correct answer is C
slope = pressure \(\div\) \(\frac{1}{volume}\)
= \(\frac{N}{m^3}\) x \(\frac{m^3}{1}\)
= Nm = work
573oC
327oC
300oC
110oC
27oC
Correct answer is E
General Gas Law:
\(\frac{P_1 V_1}{T_1}\) = \(\frac{P_2 V_2}{T_2}\)
where T\(_1\) = -73 + 273 = 200k, T\(_2\) = ?,
V\(_1\) = 1, V\(_2\) = \(\frac{1}{2V}\),
P\(_1\) = 1.5, P\(_2\) = 4.5
T\(_2\) = \(\frac{P_2 V_2 T_1}{P_1 V_1}\)
T\(_2\) = \(\frac{4.5 * 1/2 * 200}{1.5 X 1}\)
T\(_2\) → 300k or 27ºC
44oC
50oC
56oC
60oC
70oC
Correct answer is C
Heat lost = heat gained
m x (80 - \(\theta\)) x 1.5 = m x (\(\theta\) - 20) x 1
\(\theta\) = 56oC
1.503m2
1.500m2
1.498m2
1.497m2
1.490m2
Correct answer is C
\(\beta\) = A2 - A1
2 X 10-5 x 2.5 = \(\frac{A_2 \times 1.5}{1.5 \times (-20 -20)}\)
A2 = 1.498m2