\(\frac{1}{6}\)
\(\frac{1}{5}\)
\(\frac{1}{3}\)
\(\frac{4}{5}\)
\(\frac{5}{6}\)
Correct answer is E
Height inside H2O = \(\frac{2}{3}\)
R.d = \(\frac{\text{height inside}H_2O}{\text{height inside liquid}}\)
0.8 = \(\frac{\frac{2}{3}}{X}\)
6.67 x 100mm
8.50 x 102mm
1.15 x 103mm
2.50 x 103mm
1.50 x 105mm
Correct answer is A
Height = \(\frac{volume}{area}\)
= Height = \(\frac{10^3}{1.5 \times 10^2}\)
= 6.67mm
10N
100N
500N
1000N
5000N
Correct answer is D
\(\frac{load}{area}\) = \(\frac{effort}{area}\)
\(\frac{load}{5}\) = \(\frac{100}{0.5}\)
load = 1000N
15cm
12cm
10cm
8cm
5cm
Correct answer is A
Using, f1 = f2
e1 = 20 - L ; e2 = 5cm
\(\frac{f_1}{e_1}\) = \(\frac{f_2}{e_2}\)
\(\frac{100}{20 - L}\) = \(\frac{100}{5}\)
hence, L = 15cm
25N
50N
250N
500N
25 000N
Correct answer is E
F = ma
= m\(\frac{(v^2 - u^2)}{2s}\)
F = 0.05\(\frac{(0 - (500)^2)}{2 \times 0.25}\)
F = 25 000N