\(\frac{5√3m}{3}\)
5√3m
10√3m
\(\frac{10√3m}{3}\)
Correct answer is C
RQP = 90o
PQS = 30o but
RQS = 90o = \(\frac{RS}{10}\)
RS = 10 tan 60o
RS = 10 tan 60o
RS = 10√3m
If M(4, q) is the mid-point of the line joining L(p, -2) and N(q, p). Find the values of p and q
P = 2, q = 4
p = 3, q = 1
p = 5, q = 3
p = 6, q = 2
Correct answer is D
\(\frac{p + q}{2}\) = 4
p + q = 8 ....(i)
\(\frac{p - 2}{2}\) = q
p - 2q 2 ....(ii)
q = 2, p = 6
3q = 6
the perpendicular bisector of XY
a right-angled triangle
a circle
a semi circle
Correct answer is D
Since XY is a fixed line and
XPY = 90o P is on one side of XY
P1P2P3......Pn are all possible cases where
XPY = 90o the only possible tendency is a semicircle because angles in semicircle equals 90o
Calculate the perimeter, in cm, of a sector of a circle of radius 8cm and angle 45o
2\(\pi\)
8 + 2\(\pi\)
16 + 2\(\pi\)
16 + 16\(\pi\)
Correct answer is C
Perimeter = OP + OQ + PQ
= 8 + 8 + PQ
length PQ = \(\frac{\theta}{360 \times 2\pi r}\)
= \(\frac{45}{360}\) x 2 x \(\pi\) x 8
= 2\(\pi\)
Perimeter of sector 2r + L
Where l = length of arc and r = radius
∴ P = 2(8) + 2\(\pi\)
= 16 + 2\(\pi\)
11 520cm3
36 000cm3
38 200cm3
47 520cm3
Correct answer is A
Internal dimension are 50cm, 36cm and 20cm
internal volume = 50 x 36 x 20cm3
1000 x 36cm3
= 36000cm3
External dimension are 54cm x 40cm x 22cm
= 2160cm2 x 22cm = 47520cm3
Volume of wood = Ext. volume - Int. volume
= 47,520cm3 - 36,000cm3
= 11,520cm3