JAMB Mathematics Past Questions & Answers - Page 30

146.

Simplify and express in standard form \(\frac{0.00275 \times 0.00640}{0.025 \times 0.08}\)

A.

8.8 x 10-1

B.

8.8 x 10-2

C.

8.8 x 10-3

D.

8.8 x 103

Correct answer is C

\(\frac{0.00275 \times 0.0064}{0.025 \times 0.08}\)

Removing the decimals = \(\frac{275 \times 64}{2500 \times 800}\)

= \(\frac{88}{10^4}\)

88 x 10-4 = 88 x 10-1 x 10-4

= 8.8 x 10-3

147.

At what rate would a sum of N100.00 deposited for 5 years raise an interest of N7.50?

A.

\(\frac{1}{2}\)%

B.

2\(\frac{1}{2}\)%

C.

1.5%

D.

25%

Correct answer is C

Interest I = \(\frac{PRT}{100}\)

∴ R = \(\frac{100 \times 1}{100 \times 5}\)

= \(\frac{100 \times 7.50}{500 \times 5}\)

= \(\frac{750}{500}\)

= \(\frac{3}{2}\)

= 1.5%

148.

Correct 241.34(3 x 10\(^{-3}\))\(^2\) to 4 significant figures

A.

0.0014

B.

0.001448

C.

0.0022

D.

0.002172

Correct answer is D

first work out the expression and then correct the answer to 4 s.f = 241.34..............(A)

(3 x 10-\(^3\))\(^2\)............(B)

= 3\(^2\)x\(^2\)

= \(\frac{1}{10^3}\) x \(\frac{1}{10^3}\)

(Note that x\(^2\) = \(\frac{1}{x^3}\))

= 24.34 x 3\(^2\) x \(\frac{1}{10^6}\)

= \(\frac{2172.06}{10^6}\)

= 0.00217206

= 0.002172(4 s.f)

149.

Find the derivative of the function y = 2x\(^2\)(2x - 1) at the point x = -1?

A.

18

B.

16

C.

-4

D.

-6

Correct answer is B

y = 2x\(^2\)(2x - 1)
y = 4x\(^3\) - 2x\(^2\)
dy/dx = 12x\(^2\) - 4x
at x = -1
dy/dx = 12(-1)\(^2\) - 4(-1)
= 12 + 4
= 16

150.

Find the value of p if the line which passes through (-1, -p) and (-2,2) is parallel to the line 2y+8x-17=0?

A.

\(\frac{-2}{7}\)

B.

\(\frac{7}{6}\)

C.

\(\frac{-6}{7}\)

D.

2

Correct answer is D

Line:  2y+8x-17=0 

recall y = mx + c

2y = -8x + 17

y = -4x  + \(\frac{17}{2}\)

Slope m\(_1\) = 4

parallel lines: m\(_1\). m\(_2\) = -4

where Slope ( -4) = \(\frac{y_2 - y_1}{x_2 - x_1}\) at points (-1, -p) and (-2,2)

-4( \(x_2 - x_1\) ) = \(y_2 - y_1\) 

-4 ( -2 - -1) = 2 - -p

p = 4 - 2 = 2