JAMB Mathematics Past Questions & Answers - Page 318

M:N:Q == 5:4:3

i.e M = 5, N = 4, Q = 3

Substituting values into equation, we have...

\(\frac{2N - Q}{M}\)

= \(\frac{2(4) - 3}{5}\)

= \(\frac{8 - 3}{5}\)

= \(\frac{5}{5}\)

= 1

S.I. = \(\frac{P \times R \times T}{100}\)

If T = 9 months, it is equivalent to \(\frac{9}{12}\) years

S.I. = \(\frac{5000 \times 4 \times 9}{100 \times 12}\)

S.I. = N150

\(\frac{3\frac{2}{3} \times \frac{5}{6} \times \frac{2}{3}}{\frac{11}{15} \times \frac{3}{4} \times \frac{2}{27}}\)

\(\frac{\frac{11}{3} \times \frac{5}{6} \times \frac{2}{3}}{\frac{11}{15} \times \frac{3}{4} \times \frac{2}{27}}\)

\(\frac{110}{54} \div \frac{66}{1620}\)

50

2q3₅ = 77₈

2 x 5² + q x 5¹ + 3 x 5⁰ = 7 x 8¹ + 7 x 8⁰

2 x 25 + q x 5 + 3 x 1 = 7 x 8 + 7 x 1

50 + 5q + 3 = 56 + 7

5q = 63 - 53

q = \(\frac{10}{5}\)

q = 2

Man lives = \(\frac{2}{3}\) not live = \(\frac{1}{3}\)

Wife lives = \(\frac{3}{5}\) not live = \(\frac{2}{5}\)

P(at least one lives to 80 years) = P(man lives to 80 not woman) + P(woman lives to 80 and not man) + P(both live to 80)

\(P = (\frac{2}{3} \times \frac{2}{5}) + (\frac{2}{5} \times \frac{1}{3}) + (\frac{2}{3} \times \frac{3}{5})\)

= \(\frac{4}{15} + \frac{3}{15} + \frac{6}{15}\)

= \(\frac{13}{15}\)