Evaluate \(\frac{21}{9}\) to 3 significant figures
2.30
2.31
2.32
2.33
Correct answer is D
\(\frac{21}{9} = \frac{7}{3}\)
= 2.33 (to 3 sig. figs)
Simply \(\frac{2\frac{2}{3} \times 1\frac{1}{2}}{4\frac{4}{5}}\)
\(1\frac{1}{4}\)
\(1\frac{1}{6}\)
\(\frac{5}{6}\)
\(\frac{4}{5}\)
Correct answer is C
\(\frac{2\frac{2}{3} \times 1\frac{1}{2}}{4\frac{4}{5}}\)
\(\frac{8}{3} \times \frac{3}{2} \div \frac{24}{5}\)
\(\frac{8}{3} \times \frac{3}{2} \times \frac{5}{24}\)
\(\frac{5}{6}\)
Convert 112\(_6\) to a number in base three
2211
2121
1212
1122
Correct answer is D
First, convert to base 10
112\(_6\) = (1 x 6\(^2\)) + (1 x 6\(^1\)) + (2 x 6\(^0\))
= 36 + 6 + 2
= 44\(_{10}\)
\(\begin{array}{c|c} 3 & 44 \\ \hline 3 & 14 & r 2 \\ \hline 3 & 4 & r 2 \\ \hline 3 & 1 & r 1 \\ \hline 3 & 0 & r 1 \end{array}\)
Ans = 1122 = D
\(\frac{3}{8}\)
\(\frac{1}{3}\)
\(\frac{7}{24}\)
\(\frac{2}{3}\)
Correct answer is B
n(apples) = 9
n(bananas) = 8
n(oranges) = 7
n(\(\varepsilon\)) = 24
Hence Prob(not apple, nor orange) = Prob(banana) = \(\frac{8}{24}\) = \(\frac{1}{3}\)
\(\frac{1}{25}\)
\(\frac{1}{5}\)
\(\frac{4}{25}\)
\(\frac{3}{4}\)
Correct answer is C
\((1 \leq x \leq 25)\) = {1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25}
Number N of x divisible by both 2 and 3 is 4.
n(\(\varepsilon\)) = 25
= \(\frac{N}{n(\varepsilon)}\)
= \(\frac{4}{25}\)