In the figure above, PQRS is a circle with ST//RQ. Find the value of x PT = PS.
70o
55o
40o
35o
Correct answer is B
PQRS is a cyclic quad
^P = 180 - 110 (opp ∠s of a cyclic quad)
^P = 70
In ΔPTS, ^S = ^T (base ∠s of Isc Δ)
∴^T = (180-70) / 2
= 110/2
= 55o
But ^T x(corr ∠)
∴x =55
8
11/8
2/5
1/8
Correct answer is B
5-3log52 x 22log23
i Let -3log52 = p => log52-3 = p
∴2-3 = 5p
∴5-3log52 = 5log52-3 = 5p
ii 22log23 = q => log532 = q
∴32 = 2q
∴222log23 = 2q
= 32 = 9
i x ii = 2-3 x 9 = 1/23 x 9
= 1/8 x 9
= 9/8 = 11/8
| Marks | 1 | 2 | 3 | 4 | 5 |
| Frequency | 2 | 2 | 8 | 4 | 4 |
The table above show the marks obtained in a given test.
Find the mean mark
3.1
3.0
3.2
3.3
Correct answer is D
| Mark(χ) | f | fχ |
| 1 | 2 | 2 |
| 2 | 2 | 4 |
| 3 | 8 | 24 |
| 4 | 4 | 16 |
| 5 | 4 | 20 |
| ∑f = 20 | ∑fχ = 66 |
\(Mean = \frac{\sum fx}{\sum f}\)
= \(\frac{66}{20}\)
= 3.3
| Marks | 1 | 2 | 3 | 4 | 5 |
| Frequency | 2 | 2 | 8 | 4 | 4 |
The table above show the marks obtained in a given test.
How many student took the test?
16
13
20
15
Correct answer is C
∑f = 2 + 2 + 8 + 4 + 4
= 20
| Marks | 2 | 3 | 4 | 5 | 6 | 7 | 8 |
| No. of students | 3 | 1 | 5 | 2 | 4 | 2 | 3 |
from the table above, if the pass mark is 5, how many students failed the test?
6
2
7
9
Correct answer is D
| Marks | Number of students |
| 2 | 3 |
| 3 | 1 |
| 4 | 5 |
| Total | 9 |
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