55.3\(^o\)C
23.3\(^o\)C
49.0\(^o\)C
16.43\(^o\)C
Correct answer is B
\(\frac{49 - 0}{210 - 0}\) = \(\frac{\theta - 0}{100 - \theta}\)
\(\frac{49}{210} = \frac{\theta}{100}\)
49 x 100 = 210 x \(\theta\)
\(\theta = \frac{4900}{210}\) = 23.3\(^o\)
10.06cm\(^3\)
10.04 cm\(^3\)
10.02 cm\(^3\)
10.20 cm\(^3\)
Correct answer is A
3 x \(\alpha\) = \(\frac{V_2 - V_1}{V_1 \times \Delta \theta}\)
3 x 2 x 10\(^{-5}\) = \(\frac{V_2 - 10}{100 \times 10}\)
V\(_2\) = (100 x 10 x 3 x 2 10\(^{-2}\)) + 10
= 10.06 cm\(^3\)
I and II only
II only III only
III and IV only
I and III only
Correct answer is D
No explanation has been provided for this answer.
I only
II only
I and II only
II and III only
Correct answer is C
Statements I & II are correct
Statement III is incorrect because short sightedness is corrected by using suitable concave or diverging lens
Hence; option C is the correct option
10m
350m
175m
125m
Correct answer is D
Difference in time = 1 sec
echo time = 1 \(\div\) 2 = 0.5 sec
Difference of cliff from ship = 0.5 x 250
= 125m