JAMB Physics Past Questions & Answers - Page 354

1,766.

Three 4Ω resistors connected in parallel have a potential difference of 16 V applied across them. What is the total current in the circuit?

A.

14 A

B.

12 A

C.

10 A

D.

8 A

Correct answer is B

1/R = 1/4 + 1/4 + 1/4 = 3/4
R = 4/3
I = V/R

= 16
4/3

= 16 x 3
_4

= 12 A

1,767.

The diagram above shows a balanced metre bridge, the value of x is

A.

75.0 cm

B.

66.7 cm

C.

33.3 cm

D.

25.0 cm

Correct answer is C

1/R = 1/8 + 1/8 = 2/8
∴ R = 4Ω
l/l1 = R/R1
(x)/(100-x) = 4/8
4(100-x) = 8x
400-4x = 8x
400 = 8x + 4x = 12x
x = 400/12 = 33.3cm

1,769.

Three capacitors of capacitance 2μF, 4μFand 8μF are connected in parallel and a P.D of 6V is maintained across each capacitor, the total energy stored is?

A.

2.52 x 10-6J

B.

6.90 x 10-6J

C.

2.52 x 10-4J

D.

6.90 x 10-4J

Correct answer is C

C = C1 + C2 + C3
= 2 + 4 + 8 = 14μF
V = 6V
Energy = 1/2CV2
1/2 x 14 x 10-6 x 62
= 2.52 x 10-4 J

1,770.

THe velocity of sound in air at 16oC is 340ms-1. What will it be when the pressure is doubled and its temperature raised to 127ºC?

A.

400 ms-1

B.

4,000 ms-1

C.

8,000 ms-1

D.

160,000 ms-1

Correct answer is A

The velocity of sound in air, V∝√T, where T is absolute temperature
Thus V = K√T or K = V/T
V is independent of pressure and density at a fixed temperature.
∴ V1/√T1 = V2/√T2
T1 = 16 + 273 = 289K, V1 = 340ms-1
T2 = 127 + 273 = 400K, V2 = ?

340 = V2
√289 √400

 

∴ V2 = 340√400
_√289


= 400m/s