3.0 x 1014 Hz
6.0 x 1014 Hz
6.0 x 1012 Hz
2.5 x 1014 Hz
Correct answer is B
f = c/λ
| ∴ f = | c | = | 3 x 108 |
| λ | 500 x 10-9 |
=6.0 x 1014 Hz
20 Nm-1
40 Nm-1
30 Nm-1
10 Nm-1
Correct answer is A
F = Ke (Hooke's law)
K = F/e = 80/4
= 20 Nm-1
The wave phenomenon demonstrated in the diagram above is?
reflection
deflection
diffraction
refraction
Correct answer is C
Diffraction is spreading of wave after passing through a slit
4.99 x 105 Nm-2
9.80 x 103 Nm-2
4.98 x 103 Nm-2
9.80 x 105 Nm-2
Correct answer is A
PV = nRT
| ∴ P = | nRT | = | 2 x 8.313 x 300 |
| _V | ___10-2 |
= 4.987 x 105 Nm-2
The terminal velocity of a ball-bearing falling through a viscous fluid is reached when the?
upthrust is equal to the weight of the ball
ball accelerate uniformly
upthrust is equal to the velocity of the ball
velocity is uniform
Correct answer is D
At vt = terminal velocity
= zero acceleration
= uniform velocity
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