Given the inductor of inductance 5mH, 10mH and 20mH connected in series, the effective inductance is
0.35mH
3.50mH
2.90mH
35.0mH
Correct answer is D
Left = L1 + L2 + L3
= 5mH + 10mH + 20mH = 35mH
In the diagram above, the pressure of the gas is
86 cm of mercury
66 cm of mercury
96 cm of mercury
76 cm of mercury
Correct answer is A
Pressure of the Gas, P = A + h
= 76 + 10
86 cm Hg
Find the effective resistance in the diagram above
6 Ω
12 Ω
18 Ω
24 Ω
Correct answer is D
∴ Reff = R1 + R2 + .....
= 4 + 4 + 4 + 4 + 4 + 4 = 24 Ω
10 cm
15 cm
20 cm
25 cm
Correct answer is B
Magnifications = V/U = 4
∴ V = 4U
1/V + 1/U = 1/f
1/4u + 1/U = 1/12
5/4U = 1/12
4U = 12 x 5 = 60
∴ U = 15 cm
parallel to OX
parallel to OY
60o to OX
60v to OY
Correct answer is B
Particles of the transmitting medium in transverse wave oscillate in a direction perpendicular to the propagation of the wave
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