JAMB Physics Past Questions & Answers - Page 359

1,791.

The diagram above is the heating curve for a solid, QR is the?

A.

melting region

B.

boiling region

C.

sublimation region

D.

evaporating process

Correct answer is A

At melting point there is no change temperature

1,792.

The efficiency of the pulley system shown above is 80%. find the effort E required to lift the load of 1200N

A.

275N

B.

325N

C.

375N

D.

573N

Correct answer is C

VR = No. of pulleys = 4
Efficiency = \(\frac{M.A}{V.R}\) 

cross multiply

\(\frac{80}{10} * V.R\) = M.A


\(\frac{80}{10} * 4\) = M.A
M.A = 3.25
where M.A = \(\frac{load}{effort}\)
∴ Effort = \(\frac{1200}{3.2} * V.R\)

= 375N

1,793.

The diagram above shows a plank RS pivoted its center of gravity O and is in equilibrium with the weight P and Q. If a weight 2P is added to P the plank will be in equilibrium again by?

A.

moving Q nearer to O

B.

moving P nearer to O

C.

addding a weight Q to Q

D.

moving P further away from O

Correct answer is B

If 2P is added P, the beam will bend at R side. So to keep it in equilibrium. P should be moved nearer to 0

1,794.

A body of mass 4 kg resting on a smooth horizontal plane is simultaneously acted upon by two perpendicular forces 6N and 8N. Calculate the acceleration of the motion

A.

2.5 ms-1

B.

3.0 ms-1

C.

4.0 ms-1

D.

4.5 ms-1

Correct answer is A

Smooth plane has negligible friction
∴ only the resultant of the perpendicular forces is acting on the body, which is given as
F =
√ 82 + 62 

=
√ 64 + 36 

=
√ 100 

= 10N
But F = Ma
∴ a = F/M = 10/4 = 2.5 ms-1

1,795.

A force F required to keep a 5 kg mass moving round a cycle of radius 3.5 m at a speed of 7 ms-1. What is the speed, if the force is tripled?

A.

4.0 ms-1

B.

6.6 ms-1

C.

12.1 ms-1

D.

21.0 ms-1

Correct answer is C

The force which is centripetal
F = \(\frac{MV^2}{R}\)
=5 x 723.5
= 70

 

Since, force is 70 N when speed is 7m/s

Speed = ? when force 70N is trippled →  70 * 3 = 210N

210 = \(\frac{5×v^2}{3.5}\)
210 × 3.5 = 5 * v^2
735 ÷ 5 = v\(^2\)
v\(^2\) = 147
v =12.12m/s