JAMB Mathematics Past Questions & Answers - Page 365

1,821.

Evaluate 101122 - 10122

A.

1100002

B.

1102

C.

11000002

D.

110002

Correct answer is C

101122 - 10122 = (1x23 + 0x22 + 1x21 + 1x20)2 - (1x22 + 0x21 + 1x22)2
(1x8 + 0x4 + 1x2 + 1x1) 2 - (1x4 + 0x2 + 1x1) 2)
= (8 + 0 + 2 + 1) 2 - (4 + 0 + 1) 2
= 112 - 52
= 16 x 6 = 96
9610 to base 2
2/96 = 48 R 0
2/48 = 24 R 0
2/24 = 12 R 0
2/12 = 6 R 0
2/6 = 3 R 0
2/3 = 1 R 1
2/1 = 0 R 1
11000002

1,822.

Given
P = {1, 3, 5, 7, 9, 11}
and Q = {2, 4, 6, 8, 10, 12}. Determine the relationship between P and Q

A.

P∩Q = ∅

B.

P ⊂ Q

C.

Q⊂P

D.

P = Q

Correct answer is A

P = {1, 3, 5, 7, 9, 11}
Q = {2, 4, 6, 8, 1, 12}
P∩Q = {1, 3, 5, 7, 9, 11}∩{2, 4, 6, 8, 1, 12}
= {} = ∅

1,823.

A man made a profit of 5% when he sold an article for N60,000.00. How much would he have sell the article to make a profit of 26%

A.

N68,000

B.

N72,000

C.

N65,000

D.

N70,000

Correct answer is B

5% profit = 100 + 5 = 105%
26% profit = 100 + 26 = 126%
∴ 105% → N60,000
1% → 60000/15
126% = 1000/105 x 126/1
=N72,000

1,824.

If log102 = x, express log1012.5 in terms of x

A.

2(1 + x)

B.

2 + 3x

C.

2(1 - x)

D.

2 - 3x

Correct answer is D

log1012.5 = log10 121/2
= log1025/2
= log1025 - log102
= log1052 - log102
= 2log105 - log102
= 2log1010/2 - log102
= 2(1-x)- x
= 2 - 2x – x
= 2 – 3x

1,825.

Simplify \(\frac{3}{5} \div \left(\frac{2}{7} \times \frac{4}{3} \div \frac{4}{9}\right)\)

A.

\(\frac{4}{5}\)

B.

\(\frac{7}{10}\)

C.

\(\frac{6}{6}\)

D.

\(\frac{21}{6}\)

Correct answer is B

\(\frac{3}{5} \div \left(\frac{2}{7} \times \frac{4}{3} \div \frac{4}{9}\right)\\
=\frac{3}{5} \div \left(\frac{2}{7} \times \frac{4}{3} \times \frac{9}{4}\right)\\
=\frac{3}{5} \div \frac{6}{7}\\
=\frac{3}{5} \times \frac{7}{6}\\
=\frac{7}{10}\)



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