A metal of volume 40 cm3 is heated from 30 °c to 90 °c, the increase in volume is
0.12 cm3
4.00 cm3
1.20 cm3
0.40 cm3
no correct option
Correct answer is E
increase in volume, DV = RV1 ∆ θ = 3α Vsub>1 Dθ
= 3 x 2.0 X 10-5 x 40 x (90 - 30)
= 6 x 10-5 x 40 x 60
0.144 cm3
∴ No correct option
50 N
520 N
220 N
80 N
Correct answer is D
upthrust = weight in air - weight in liquid = 30 x 10 - 22 x 10 = 300 - 220 = 80 N
If a tube of small radius opened at both ends is placed in a liquid, the liquid will
remain at the same level irrespective of whether the liquid wet the glass or not
fall below the liquid level if the liquid wets the glass
falls below the liquid level if the liquid does not wet the glass
rise above the liquid level if the liquid does not wet the glass
Correct answer is C
The liquid will rise up the capillary if it wets glass and falls below its wets glass and falls below its initial level if it does not wet glass
600 J
150 J
300 J
450 J
Correct answer is C
K e just before hitting the gound
= P e at the maximum height (conservation of mechanical energy)
K e = P e = mgh = 1.5 x 10 x 20
= 300 J
25 N
100 N
50 N
40 N
Correct answer is C
Centripetal force,
F = \( \frac{mv^2}{r} \)
= \( \frac{2 \times 10^2}{4} \)
= \( \frac{200}{4} \)= 50N