A woman buys 270 oranges for N1800.00 and sells at 5 for N40.00. What is her profit?
N2,160.00
N1, 620.00
N630.00
N360.00
Correct answer is D
C.P = N1800
S.P = (270/5) x 40 = N2160.00
Profit = S.P - C.P = N2160 - N1800 = N360.00
Find (\(\frac{1}{0.06} \div \frac{1}{0.042}\))-1
1.43
1.53
3.14
4.42
Correct answer is A
\((\frac{1}{0.06} \div \frac{1}{0.042})^{-1}\)
= \((\frac{100}{6} \div \frac{1000}{42})^{-1}\)
= \((\frac{100}{6} \times \frac{42}{1000})^{-1}\)
= \((\frac{7}{10})^{-1}\)
= \(\frac{10}{7}\)
= 1.4285 \(\approxeq\) 1.43.
20
16
8
4
Correct answer is A
Using a venn diagram, let x = number who offer both Maths and Physics. So that (32-x) offer Maths and another (24-x) offer Physics.
(32-x) + (24-x) + (x) + (4 who offer neither) = 40
=> 60 - x = 40
=> -x = -20
Therefore x = 20.
103114
103214
122314
132114
Correct answer is C
You can either multiply directly in base 4 or you can decide to convert to base 10 and do the multiplication and re-convert.
Evaluate \(log_{\sqrt{2}}4+log_{\frac{1}{2}}16-log_{4}32\)
-5.5
-2.5
2.5
5.5
Correct answer is B
Note that if we set \(log_{\sqrt{2}}4 = x_{1}, \hspace{1mm}solving\hspace{1mm}gives\hspace{1mm}x_{1}=4\\if\hspace{1mm}log_{\frac{1}{2}}16 = x_{2}, \Rightarrow x_{2} = -4\\Also \hspace{1mm}for\hspace{1mm}log_{4}32 = x_{3} = 2.5\\Combining\hspace{1mm}results,\hspace{1mm}x_{1}+x_{2}+x_{3} = 4+(-4)-2.5=-2.5\)
Note that the solution has been separated to simplify solving difficulty due to different bases.