JAMB Mathematics Past Questions & Answers - Page 409

2,041.

If the gradient of the curve y = 2kx2 + x + 1 at x = 1 is 9, find k.

A.

4

B.

3

C.

2

D.

1

Correct answer is C

y = 2kx2 + x + 1
Gradient function dy/dx = 4kx + 1
at dy/dx = 9, => 9 = 4kx + 1
=> 8 = 4kx, and k = 8/4x.

At x = 1, k = 8/4 = 2

2,042.

The chord ST of a circle is equal to the radius, r, of the circle. Find the length of arc ST.

A.

πr/6

B.

πr/2

C.

πr/12

D.

πr/3

Correct answer is D

Since ST = the radius r, => SOT is equilateral.
Each angle = 60°
Length of arc ST = θ/360 x 2πr
= 60/360 x 2 x π x r = πr/3

2,043.

Find the locus of a point which moves such that its distance from the line y = 4 is a constant, k.

A.

y = 4 \(\pm\) k

B.

y = k \(\pm\) 4

C.

y = 4 + k

D.

y = k - 4

Correct answer is A

No explanation has been provided for this answer.

2,044.

A cylindrical tank has a capacity of 3080m3. What is the depth of the tank if the diameter of its base is 14m? Take pi = 22/7.

A.

23 m

B.

25 m

C.

20 m

D.

22 m

Correct answer is C

Capacity = Volume = 3080m3

base diameter = 14m

radius = \(\frac{\text{diameter}}{2}\)

= 7m

Volume of Cylidner = Capacity of cylinder

πr2h = 3080

\(\frac{22}{7}\) × 7 × 7 × h = 3080

h = \(\frac{3080}{22 \times 7}\)

h = 20m

2,045.

The bearings of P and Q from a common point N are 020° and 300° respectively. If P and Q are also equidistant from N, find the bearing of P from Q.

A.

040°

B.

070°

C.

280°

D.

320°

Correct answer is B

Hint: Simply make a sketch of the question and find the bearing to be 070°