JAMB Physics Past Questions & Answers - Page 413

2,061.

In an ideal wheel an axle system, R stand for the radius of the wheel and r is the radius of the axle. the mechanical advantage is

A.

(R/r)2

B.

r/R

C.

(r/R)2

D.

R/r

Correct answer is D

In a wheel and axle system of mechanic, the mechanical advantage is given by its ratio of the radius of the wheel R, to the radius of the axle r. that M.A = R/r

2,062.

The pair of physical quantities consisting of vectors only are

A.

momentum and power

B.

velocity and distance

C.

displacement and torgue

D.

accelaration and speed

Correct answer is C

No explanation has been provided for this answer.

2,063.

A real image three times the size of an object is formed 24cm from a converging mirror. what is the focal length of the mirror.

A.

16cm

B.

6cm

C.

8cm

D.

12cm

Correct answer is B

for a real image 3 times the size of the object, it implies that the magnification 3 = v/u, 3 = 24/u, therefore 3u = 24, u = 8cm thus we have from the relation:m = (f)/(u)-f; that 3 = (f)/(8) - f. therefore f = 3(8-f) f = 24 - 3f ∴4f = 24; f = 6cm OR: (1)/(u) + (1)/(v) = (1)/(f).
(1)/(8) + (1)/(24) = (1)/(f)
therefore (3+1)/(24) = (1)/(f)
4/24=1/f;therefore 4f = 24
f = 6cm

2,064.

A thin converging lens has a power of 4.0 diopters determined its focal length.

A.

2.50m

B.

0.03m

C.

5.00m

D.

0.25m

Correct answer is D

the power of a lens is defined as the reciprocal of the focal length ,expressed in metre.Mathematically, the power of a lens in dioptres is given by:(1)/f(in cm).
thus for lens of power of 4.0 dioptres we have that: (1)/(f) = +4.0
f= (1)/(4.0) 
= 0.25cm

2,065.

The sharpness of the boundary of the shadow of an object is determined by the

A.

intensity of light striking the object

B.

rays of light passing through the object

C.

nature of the object

D.

opacity of the object

Correct answer is B

The sharpness of the boundary of the shadow of an object is determined by the rays of light passing through the object. The smaller the rays passing through , that is from a point source, the more sharp the shadow becomes, but the more the rays, that is rays from a large source, the more blurred the shadow becomes.