When temperature of a liquid increases, its surface tension
Decreases
Increases
Remain Constant
Increases then decreases
Correct answer is A
No explanation has been provided for this answer.
5/3
4/3
3/4
7/10
Correct answer is C
R.D = loss in weight in liquid X loss in weight in water.
R.D = (10 - 7)/(10 - 6) = 3/4
5 . 0 x 104 Nm-2
5 . 0 x 105 Nm-2
2 . 0 x 108 Nm-2
2 . 0 x 109 Nm-2
Correct answer is D
Y = stress/strain, but stress = 107Nm-2 (given).
Strain = e/l0. = (10.05 - 10.00)/10.00 = 0.005
Thus Y = 107/0.005 = 2 . 0 x 109Nm-2
When the brakes in a car are applied, the frictional force force on the tyres is
is a disadvantage because it is in the direction of the motion of the car
is a disadvantage because it is in the opposite direction of the motion of the car
is an advantage because it is in the direction of the motion of the car
is an advantage because it is in the opposite direction of the motion of the car
Correct answer is D
No explanation has been provided for this answer.
A car of mass 800kg attains a speed of 25m/s in 20 secs. The power developed in the engine is
1 . 25 x 104 W
2 . 50 x 104 W
1 . 25 x 106W
2 . 50 x 106 W
Correct answer is B
Power = Force x \(\frac{distance}{time}\) = \(\frac{m(v - u)}{t} \times v\)
\(\frac{800(25 - 0)}{20} \times 25\)
= 2.5 x 10\(^{4}\) watts