JAMB Chemistry Past Questions & Answers - Page 62

306.

The choice of method for extracting a metal from its ores depends on the

A.

strength of the core

B.

position of the metal in the electrochemical series

C.

source of the core

D.

position of the metal in the periodic table

Correct answer is B

The method used to extract a metal from its ore depends upon the stability of its compound in the ore, which in turn depends upon the reactivity of the metal:

  • The oxides of very reactive metals, such as aluminum, form stable oxides and other compounds. A lot of energy is needed to reduce them to extract the metal.

  • The oxides of lesser reactive metals, such as iron, form less stable oxides and other compounds. Relatively little energy is needed to reduce them to extract the metal.

  So, the method of extraction of a metal from its ore depends on the metal's position in the reactivity series.

307.

Calculate the pH of 0.05 moldm\(^{-3}\) H\(_2\)SO\(_4\)

A.

1.30

B.

1.12

C.

1.00

D.

0.30

Correct answer is C

Recall from pH formula pH = -Log [H+]

  H2SO4 → 2H+ + SO42-

  2H+ → 2 X0.05 = 0.1

  pH= -Log [0.1] = 1

308.

What mass of Cu would be produced by the cathodic reduction of Cu\(^{2+}\)  when 1.60A of current passes through a solution of CuSO\(_4\) for 1 hour. (F=96500Cmol\(^{-1}\) , Cu=64)

A.

7.64g

B.

3.82g

C.

1.91g

D.

0.96g

Correct answer is C

M = \(\frac{MmIT}{96500n}\)

  Where

  M=mass

  Mm = Molar mass = 64g/mol

  I = current = 1.6A

  T= Time  =1h r=3600s

  N= No of Charge = +2

  M = \(\frac{64x \times 1.6 \times 3600}{96500 \times 2}\)

  M=1.91g

309.

The solubility of the solids that dissolves in a given solvent with the liberation of heat will

A.

increase with an increase in temperature

B.

decrease with an increase in temperature

C.

decrease with a decrease in temperature

D.

not be affected by changes in temperature

Correct answer is B

Increasing temperature in exothermic reaction favors the left/reactant side and decreasing temperature will favor the right/product side.

310.

Diamond is a bad conductor of electricity because its bonding electrons are used in

A.

crystal lattice formation

B.

covalent bond formation

C.

metallic bond formation

D.

coordinate bond formation

Correct answer is B

Diamond is a covalent macromolecule, and typical of a covalent substance is an insulator. All valence electrons are localized in well-defined covalent bonds and hence are not free to move through the structure