3,600J
6,000J
7,200J
14,400J
Correct answer is C
Power drawn by the resistor = IV = (2)(3) = 24W = 24J/s
Energy dissipated = power × time = (24)(5)(60) = 7200J
1.10Ω
1.64Ω
2.44Ω
27.50Ω
Correct answer is C
\(\frac{R_1}{R_2}\) = \(\frac{L_1}{(100 − L_1)}\)
\(\frac{R_1}{2}\) = \(\frac{55}{45}\)
R\(_1\) = 2 × \(\frac{55}{45}\)
= 2.44Ω
10cm
20cm
30cm
40cm
Correct answer is D
F= 15cm
M = 3
M = \(\frac{v}{u}\)
V =3u
\(\frac{1}{f}\) = \(\frac{1}{u}\) + \(\frac{1}{v}\)
\(\frac{1}{15}\) = \(\frac{1}{u}\) - \(\frac{1}{3u}\)
\(\frac{1}{15}\) = \(\frac{2}{3u}\)
U =10cm
D = u + v
= 10 +30 = 40cm
3.75cm
6.70cm
10.00cm
-15.00cm
Correct answer is D
V = -6cm
M = 0.6cm
Recall m = \(\frac{V}{U}\)
U = \(\frac{V}{M}\)
U = \(\frac{6}{0.6}\)
U = 10
\(\frac{1}{U}\) + \(\frac{1}{V}\) = \(\frac{1}{F}\)
\(\frac{1}{10}\) + \(\frac{1}{-6}\) = \(\frac{1}{F}\)
\(\frac{-4}{60}\) = \(\frac{1}{F}\)
F = \(\frac{60}{-4}\)
= -15cm
17cm
20cm
25cm
100cm
Correct answer is C
No explanation has been provided for this answer.