14.67cm
73.33 cm
101.33cm
513.33cm
Correct answer is C
Length of the arc = \(\frac{\theta}{360} \times 2\pi r\)
= \(\frac{300}{360} \times 2 \times \frac{22}{7} \times 14\)
= \(\frac{220}{3}\)
= 73.33 cm
Perimeter of the sector = Length of the arc + 2r
= 73.33 + 2(14)
= 101.33 cm
\(\frac {1}{10}\)
\(\frac {2}{10}\)
\(\frac {9}{20}\)
\(\frac {11}{20}\)
Correct answer is D
Pr(both John and James passed)
= \(\frac {3}{4}\) x \(\frac {3}{5}\)
= \(\frac {9}{20}\)
Pr(john and james failed)= 1- Pr(john and james passed)
= 1 – \(\frac {9}{20}\)
= \(\frac {11}{20}\)
Answer is D
Convert 0.04945 to two significant figures
0.040
0.049
0.050
0.49
Correct answer is B
No explanation has been provided for this answer.
If \(\frac{x}{a + 1}\) + \(\frac{y}{b}\) = 1. Make y the subject of the relation.
\(\frac{b(a + 1 - x)}{a + 1}\)
\(\frac{a + 1}{b(a - x + 1)}\)
\(\frac{a(b - x + 1)}{b + 1}\)
\(\frac{b}{a(b - x + 1)}\)
Correct answer is A
No explanation has been provided for this answer.
\(\frac{5}{6}\)
\(\frac{7}{12}\)
\(\frac{5}{12}\)
\(\frac{1}{6}\)
Correct answer is C
let the girls' initial pocket money be whole(1)
\(\frac{1}{4}\) of 1 = books, \(\frac{1}{3}\) of 1 = dress
fraction of her money left = 1 - \(\frac{1}{4}\) - \(\frac{1}{3}\)
= \(\frac{5}{12}\)