JAMB Physics Past Questions & Answers - Page 71

351.

An object is placed 20cm from a concave mirror of focal length 10cm. The linear magnification of the image produced is?

A.

0

B.

\(\frac{1}{2}\)

C.

1

D.

2

Correct answer is C

\(\frac{I}{V}\) = \(\frac{1}{f}\) – \(\frac{1}{u}\)

\(\frac{I}{V}\) = \(\frac{1}{10}\) – \(\frac{1}{20}\)

  = \(\frac{1}{20}\) V

  V = 20cm.

  M = \(\frac{V}{U}\)

  = \(\frac{20}{20}\)

  = 1

352.

The tendency of a body to remain at rest when a force is applied to it is called.

A.

Impulse

B.

Momentum

C.

Inertia

D.

Friction

Correct answer is C

Inertia, property of a body by virtue of which it opposes any agency that attempts to put it in motion or, if it is moving, to change the magnitude or direction of its velocity. Inertia is a passive property and does not enable a body to do anything except oppose such active agents as forces and torques. A moving body keeps moving not because of its inertia but only because of the absence of a force to slow it down, change its course, or speed it up.
There are two numerical measures of the inertia of a body: its mass, which governs its resistance to the action of a force, and its moment of inertia about a specified axis, which measures its resistance to the action of a torque about the same axis.

353.

A 20kg mass is to be pulled up a slope inclined at 30° to the horizontal. If efficiency of the plane is 75%. The force required to pull the load up the plane is J [g=10ms\(^{− 2}\)]

A.

87N

B.

73.5N

C.

133.3N

D.

533.2N

Correct answer is C

V. R = \(\frac{1}{Sinθ}\)

  m = 20kg

  V.R = \(\frac{1}{Sin 30}\)

  = 2

  Efficiency = 75%

  Load = mg

  = 20 x 10 = 200N

  Efficiency = \(\frac{M.A}{V.R} \times 100\)

  75/100 = \(\frac{M.A}{2}\)

  M .A = \(\frac{75 \times 2}{100}\)

  M. A = 1.5

  Since M. A. = \(\frac{\text{Load}}{\text{Force}}\)

  Force = \(\frac{200}{1.5}\)

  = 133.3N

354.

A body of mass 100g moving with a velocity of 10ms-1 collides with a wall. If after collision it moves with a velocity of 2.0ms−1 in the opposite direction, calculate the change in momentum.

A.

0.8Ns

B.

1.2Ns

C.

12.0Ns

D.

80.0Ns

Correct answer is B

Momentum = Mass x Velocity
Change in Momentum = Mass x (change in velocity)
Change in Momentum = Mass x (v - u)
Mass = 100g = 0.1kg
U = 2ms\(^{-1}\)
V = 10ms\(^{-1}\)
Change in momentum = m (v − u)
= 0.1 (2 -(- 10))
= 0.1 (12)
= 1.2Ns

355.

The force between the molecules of a liquid in contact with that of a solid is?

A.

Adhesive

B.

Cohesive

C.

Magnetic

D.

Repulsive

Correct answer is A

The term Adhesive forces refers to the attractive forces between unlike substance