4
8
16
20
Correct answer is D
Let the number of people that offer both Mathematics and Physics = y
Then, \((32 - y) + y + (24 - y) + 4 = 40\)
\(60 - y = 40 \implies y = 20\)
\(\therefore\) 20 students offer both Mathematics and Physics.
What is the product of 2x2 − x + 1 and 3 − 2x
4x3 − 8x2 + 5x + 3
−4x3 + 8x2 − 5x + 3
−4x3 − 8x2 + 5x + 3
4x3 + 8x2 − 5x + 3
Correct answer is B
(2x2 - x + 1) × (3 - 2x);
3(2x2 - x + 1) - 2x (2x2 - x + 1)
6x2 - 3x + 3 - 4x3 + 2x2 - 2x
-4x3 + 8x2 -5x + 3
Evaluate 1 − (\(\frac{1}{5}\) x 1\(\frac{2}{3}\)) + (5 + 1\(\frac{2}{3}\))
4
3
\(\frac{22}{3}\)
3\(\frac{2}{3}\)
Correct answer is C
1 − (\(\frac{1}{5}\) x 1\(\frac{2}{3}\)) + (5 + 1\(\frac{2}{3}\))
1 − (\(\frac{1}{5}\) x \(\frac{5}{3}\)) + (5 + \(\frac{5}{3}\))
1 − \(\frac{1}{3}\) + \(\frac{20}{3}\)
= \(\frac{22}{3}\)
Find the range of the following set of numbers 0.4, −0.4, 0.3, 0.47, −0.53, 0.2 and −0.2
1.03
0.07
0.03
1.0
Correct answer is D
0.4, −0.4, 0.3, 0.47, −0.53, 0.2, −0.2 Range is the difference between the highest and lowest value i.e Highest − Lowest − 0.53, −0.4, −0.2, 0.2, 0.3, 0.4, 0.47 0.47 is the highest − 0.53 is the lowest ∴ = 0.47 − (− 0.53) ∴0.47 + 0.53 = 1.0
If α and β are the roots of the equation 3x2 + 5x - 2 = 0, find the value of 1/α + 1/β
\(\frac{-5}{3}\)
\(\frac{-2}{3}\)
\(\frac{1}{2}\)
\(\frac{5}{2}\)
Correct answer is D
1/α + 1/β = β+α/αβ
3x2 + 5x - 2 = 0
x2 + 5x/3 - 2/3 = 0
αβ = -2/3
β+α = -5/3
Thus; β+α/αβ = -2/3 -2/3 = -5/2