JAMB Physics Past Questions & Answers - Page 77

382.

The electrochemical equivalent of silver is 0.0012g/C. If 36.0g of silver is to be deposited by electrolysis on a surface by passing a steady current for 5mins, the current must be?

A.

6000A

B.

100A

C.

10A

D.

1A

Correct answer is B

Given Data: Mass of Ag = 36.0g,

Z which is electrochemical equivalent of Ag = 0.0012coulomb

 t = 5mins →  5 * 60 = 300secs.

Using M =Z * I * t

make I the subject of the formula
I = \(\frac{M}{Z * t}\)  → \(\frac{36}{0.0012 * 300}\)

Current (I) =  100A

383.

The amount of heat needed to raise the temperature of 10kg of Copper by 1K is its

A.

specific heat capacity

B.

latent heat

C.

heat capacity

D.

internal energy

Correct answer is C

The heat capacity of a defined system is the amount of heat (usually expressed in calories, kilocalories, or joules) needed to raise the system's temperature by one degree (usually expressed in Celsius or Kelvin).

384.

What type of reaction is represented by the following scheme?
\(_{1} ^{2} X\) + \(_{1} ^{2} Y\)  -----> \(_{2} ^{3} Z\) + \(_{0} ^{1} n\) + energy

A.

fusion reaction

B.

fission reaction

C.

Chain reaction

D.

radioactive decay

Correct answer is A

No explanation has been provided for this answer.

385.

The diagram shown represents a block-and-tackle pulley system on which an effort of W Newtons supports a load of 120.0N. If the efficiency of the machine is 40, then the value of W is?

A.

28.0

B.

48.0N

C.

233.0N

D.

50.0N

Correct answer is D

Given Data:

Efficiency = 40% Load = 120N, V.R = 6 (Number of Pulleys)

Efficiency = \(\frac{M.A}{V.R} * 100\)

40 = \(\frac{M.A}{6} * 100\)

6 * 40 = 100 M.A

M.A = \(\frac{240}{100}\) → 2.4

Where M.A = \(\frac{Load}{Effort}\) 

2.4 = \(\frac{120}{Effort}\)

: Effort = \(\frac{120}{2.4}\)  → 50N