JAMB Mathematics Past Questions & Answers - Page 78

386.

Simplify 4\(\sqrt{27}\) + 5\(\sqrt{12}\) − 3\(\sqrt{75}\)

A.

7

B.

− 7

C.

− 7\(\sqrt{3}\)

D.

7\(\sqrt{3}\)

Correct answer is D

4\(\sqrt{27}\) + 5\(\sqrt{12}\) − 3\(\sqrt{75}\)

= 4\(\sqrt{3}\) × 9 + 5\(\sqrt{3}\) × 4 − 3\(\sqrt{3}\) × 25

= 4 × 3\(\sqrt{3}\) + 5 × 2\(\sqrt{3}\) − 3 × 5\(\sqrt{3}\)

= 12\(\sqrt{3}\) + 10\(\sqrt{3}\) − 15\(\sqrt{3}\)

= (12 + 10 − 15)\(\sqrt{3}\)

= 7\(\sqrt{3}\)

387.

A cylindrical tank has a capacity of 3080m3. What is the depth of the tank if the diameter of its base is 14m? Take pi = 22/7.

A.

23m

B.

25m

C.

20m

D.

22m

Correct answer is C

Capacity = Volume = 3080m3

base diameter = 14m

radius = \(\frac{\text{diameter}}{2}\)

= 7m

Volume of Cylidner = Capacity of cylinder

πr2h = 3080

\(\frac{22}{7}\) × 7 × 7 × h = 3080

h = \(\frac{3080}{22 \times 7}\)

h = 20m

388.

In a regular polygon, each interior angle doubles its corresponding exterior angle. Find the number of sides of the polygon

A.

8

B.

6

C.

4

D.

3

Correct answer is B

2x + x = 180o

3x = 180o

x = 60o (exterior angle of the polygon)

angle = \(\frac{\text{total angle}}{\text{number of sides}}\)

60 = \(\frac{360}{n}\)

n = \(\frac{360}{60}\)

n = 6 sides

389.

The value of x + x ( xx) when x = 2 is

A.

16

B.

10

C.

18

D.

24

Correct answer is B

when x=2, we have

\(2 + 2(2^{2})\) = \(2 + 8 = 10\)

390.

The base in which the operation was performed was

A.

6

B.

2

C.

4

D.

5

Correct answer is B

No explanation has been provided for this answer.