JAMB Physics Past Questions & Answers - Page 8

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71.

Find the tension in the two cords shown in the figure above. Neglect the mass of the cords, and assume that the angle is 38° and the mass m is 220 kg

[Take g = 9.8 ms-2]

A.

\(T_1\) = 2864 N, \(T_2\)= 3612 N

B.

\(T_1\)= 3612 N, \(T_2\) = 2864 N

C.

\(T_1\)= 3502 N, \(T_2\)= 2760 N

D.

\(T_1\) = 2760 N, \(T_2\) = 3502 N

Correct answer is C

W =  mg  = 220 x 9.8 = 2156 N


⇒Sin 38º = \(\frac{2156}{T_1}\)

⇒ \(T_1\) =    \(\frac{2156}{Sin 38}\)

⇒ \(T_1\) =     3502 N

 

Cos 38º =  \(\frac{T_2}{T_1}\)

⇒ \(T_2\)  =   3502 x Cos 38º

⇒ \(T_2\) =   2760 N

 

;    \(T_1\) =   3502 N,  \(T_2\) = 2760 N.

 

 

72.

Which of the following statements regarding the application of electrical conduction via gases is/are correct?
Electrical conduction in gas is applied in:
(i) The identification of gases
(ii) Lighting/fluorescent tubes
(iii) Photocells
(iv) Cathode ray oscilloscope/T.V. tubes

A.

(i), (iii) and (iv) only

B.

(i), (ii) and (iv) only

C.

(ii), (iii) and (iv) only

D.

(i), (ii) and (iii) only

Correct answer is B

Electrical conduction of gas is applied in:
(i) The identification of gases
(ii) Lighting/fluorescent tubes
(iii) Advertising industry/Neon signs
(iv) Cathode ray oscilloscope/T.V. tubes

73.

The property of wave shown in the diagram above is?

A.

Diffraction

B.

Refraction

C.

Polarisation

D.

Interference

Correct answer is A

Diffraction is the bending of waves around the corners of an obstacle or through an aperture.

74.

If an object just begins to slide on a surface inclined at 30º to the horizontal,the coefficient of friction is?

A.

√3

B.

\(\frac{√3}{2}\)

C.

\(\frac{1}{√2}\)

D.

\(\frac{1}{√3}\)

Correct answer is D

A body sliding down a plane inclined at 30o to the horizontal,

Has coefficient of friction = tan 30º  or \(\frac{1}{√3}\)

75.

The mercury column in the barometer at notational  atmospheric pressure has a height of?

A.

0.76 cm at see level

B.

760 cm at sea level

C.

7.6 cm at sea level

D.

76 cm at sea level

Correct answer is D

The height of the mercury column serves as an indicator of atmospheric pressure. At sea level and at a temperature of 0° Celsius (C), the height of the mercury column is approximately 30 inches, or 76 centimeters. This represents a pressure of approximately 14.7 psia. The 30-inch column is used as a reference standard.

76.

One of the following is a scalar quantity?

A.

weight

B.

momentum

C.

potential energy

D.

displacement

Correct answer is C

Examples of scalar quantities are mass, energy, distance, charge, volume, time, speed, and the magnitude of physical vectors in general

77.

A semiconductor is formed by?

A.

co-ordinate bonds

B.

electrovalent bonds

C.

a substance free of bonds

D.

covalent bonds

Correct answer is D

It's generally created using silicon, germanium, or other pure elements.

Semiconductors are created by adding impurities to the element.

The conductance or inductance of the element depends on the type and intensity of the added impurities.

The electrons surrounding each atom in a semiconductor are part of a covalent bond

78.

The main factor which affects the speed of sound wave is the?

A.

properties of the medium

B.

amplitude of the sound wave

C.

intensity of the sound wave

D.

loudness of the sound wave

Correct answer is A

Factors Affecting The Speed of Sound

  • The Density of Medium: Sound requires a medium to travel. The density of the medium is among the factors which affect the speed of sound. ...
  • The Temperature of The Medium: Higher the temperature, the higher is the speed of sound in the medium.

79.

A train of mass 1600 kg attains a speed of 25 ms\(^{-1}\) in 20 seconds. The power developed in the engine is?

A.

2.5 KW

B.

80 KW

C.

25 KW

D.

50 KW

Correct answer is D

where force = f, mass = m, acceleration = a, velocity = v, time = t

Force = m * a → m * \(\frac{Δv}{t}\) 

Power = f * v

P = m * \(\frac{v}{t}\)  * v = m * \(\frac{v^2}{t}\) 

p =  \(\frac{1600 * 25^2}{20}\) 

p = 50,000 or 50 KW

80.

What quantity of heat is required to convert 20 g of ice at 0 ºC to water at the same temperature? (Specific latent heat of ice = 336 Jg\(^{-1}\))

A.

7.06 x 10\(^{3}\)J

B.

5.38 x 10\(^{3}\)J

C.

6.72 x 10\(^{3}\)J

D.

1.35 x 10\(^{3}\)J

Correct answer is C

quantity of heat = mass * Specific latent heat → 20 * 336 

quantity of heat = 6720j or  6.72 x 10\(^{3}\)J