Further Mathematics Questions and Answers
Test your knowledge of advanced level mathematics with this aptitude test. This test comprises Further Maths questions and answers from past JAMB and WAEC examinations.
Test your knowledge of advanced level mathematics with this aptitude test. This test comprises Further Maths questions and answers from past JAMB and WAEC examinations.
18.91
19.75
25.63
38.23
Correct answer is C
\(y = 19.33 + 0.42x\)
\(\text{The value of y when x = 15} = 19.33 + (0.42 \times 15)\)
= \(19.33 + 6.30\)
= 25.63
\(\frac{1}{5}\)
\(\frac{2}{5}\)
\(\frac{3}{5}\)
\(\frac{4}{5}\)
Correct answer is B
No explanation has been provided for this answer.
| Age(in years) | 1 - 5 | 6 - 10 | 11 - 15 |
| Frequency | 3 | 5 | 2 |
Calculate the standard deviation of the distribution.
1.10
2.36
3.50
7.50
Correct answer is C
|
Age (years) |
Freq (f) |
Mid-value (x) |
fx | \(d = (x - \bar{x})\) | \(d^{2}\) | \(fd^{2}\) |
| 1 - 5 | 3 | 3 | 9 | - 4.5 | 20.25 | 60.75 |
| 6 - 10 | 5 | 8 | 40 | 0.5 | 0.25 | 1.25 |
| 11 - 15 | 2 | 13 | 26 | 5.5 | 30.25 | 60.5 |
| \(\sum =\) | 10 | 75 | 122.5 |
\(Mean (\bar {x}) = \frac{\sum fx}{\sum f} = \frac{75}{10} = 7.5\)
\(SD = \sqrt{\frac{\sum fd^{2}}{\sum f}}\)
= \(\sqrt{\frac{122.5}{10}}\)
= \(\sqrt{12.25} = 3.50\)
1.5 s
3.0 s
4.0 s
6.0 s
Correct answer is B
\(F = ma \)
\(10 = 2.5a \implies a = 4 ms^{-2}\)
Since it is a retarding movement, then \(a = -4 ms^{-2}\).
\(v = u + at; v = 0 ms^{-1}, u = 12 ms^{-1}\)
\(0 = 12 + (-4t) \implies 0 = 12 - 4t\)
\(4t = 12 \implies t = 3 s\)
1 cm
\(\sqrt{2}\) cm
2 cm
4 cm
Correct answer is C
The area of sector in radians = \(\frac{r^{2} \theta}{2}\)
\(3 cm^{2} = \frac{1.5 \times r^{2}}{2}\)
\(r^{2} = \frac{3 \times 2}{1.5} = 4\)
\(r = 2 cm\)