A particle of mass 2.5 kg is moving at a speed of 12 m/s....
A particle of mass 2.5 kg is moving at a speed of 12 m/s. If a force of magnitude 10 N acts against it, find how long it takes to come to rest.
1.5 s
3.0 s
4.0 s
6.0 s
Correct answer is B
F=ma
10=2.5a⟹a=4ms−2
Since it is a retarding movement, then a=−4ms−2.
v=u+at;v=0ms−1,u=12ms−1
0=12+(−4t)⟹0=12−4t
4t=12⟹t=3s
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