How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
2.00
3.67
8.67
11
Correct answer is D
Log2(3x - 1) = 5
Log2(3x - 1) = Log225
Log2(3x - 1) = Log232
3x - 1 = 32
3x = 32 + 1 = 33
x = \(\frac{33}{3}\)
= 11
The marks of eight students in a test are: 3, 10, 4, 5, 14, 13, 16 and 7. Find the range
16
14
13
11
Correct answer is C
First, arrange the marks in order of magnitude; 3, 4, 5, 7, 10, 13, 14, 16
Hence range = 16 - 3 = 13
A fair die is thrown two times. What is the probability that the sum of the scores is at least 10?
\(\frac{5}{36}\)
\(\frac{1}{6}\)
\(\frac{5}{18}\)
\(\frac{2}{3}\)
Correct answer is B
\(\begin{array}{c|c}
& 1 & 2 & 3 & 4 & 5 & 6 \\
\hline
1 & 1,1 & 1,2 & 1,3 & 1,4 & 1,5 & 1,6 \\ \hline 2 & 2,1 & 2,2 & 2,3 & 2,4 & 2,5 & 2,6 \\ \hline 3 & 3,1 & 3,2 & 3,3 & 3,4 & 3,5 & 3,6 \\ \hline 4 & 4,1 & 4,2 & 4,3 & 4,4 & 4,5 & 4,6 \\ 5 & 5,1 & 5,2 & 5,3 & 5,4 & 5,5 & 5,6 \\ \hline 6 & 6,1 & 6,2 & 6,3 & 6,4 & 6,5 & 6,6\end{array}\)
From the table above, event space, n(E) = 6
sample space, n(S) = 36
Hence, probability sum of scores is at least 10, is;
\(\frac{n(E)}{n(S)}\)
= \(\frac{6}{36}\)
= \(\frac{1}{6}\)
Le 2,250,000.00
Le 22,700,000.00
Le 3,600,000.00
Le 4,500,000.00
Correct answer is C
sectoral angle representing food
= 360o - (80 + 70 + 90)o
= 120o
Amount spent on food
= \(\frac{\tect{sectoral angle}}{360^o}\) x Le 10,800,000
= Le 3,600,000
In the diagram, TX is perpendicular to UW, |UX| = 1cm and |TX| = |WX| = \(\sqrt{3}\)cm. Find UTW
135o
105o
75o
60o
Correct answer is C
In \(\Delta\) UXT, tan\(\alpha\) = \(\frac{1}{\sqrt{3}}\)
\(\alpha\) = tan-1(\(\frac{1}{\sqrt{3}}\))
= 30o
In \(\Delta\)WXT, tan\(\beta\) \(\frac{\sqrt{3}}{\sqrt{3}}\) = 1
\(\beta\) = tan-1(1) = 45o
Hence, < UTW = \(\alpha\) + \(\beta\)
= 30o + 45o = 75o