Mathematics questions and answers

Mathematics Questions and Answers

How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.

976.

Find the area of a triangle ABC such that a = 16cm, b = 14cm, c = 12cm, leave your answer in surd form

A.

5\(\sqrt{15}\)cm2

B.

7\(\sqrt{15}\)cm2

C.

21\(\sqrt{3}\)cm2

D.

21\(\sqrt{5}\)cm2

E.

21\(\sqrt{15}\)cm2

Correct answer is E

No explanation has been provided for this answer.

977.

Evaluate \(1011_{two}\) + \(1101_{two}\) + \(1001_{two}\) - \(111_{two}\)

A.

10001\(_{two}\)

B.

11001\(_{two}\)

C.

110001\(_{two}\)

D.

11010\(_{two}\)

E.

10001\(_{two}\)

Correct answer is D

Convert each value to decimal (base 10)

\(1011_{two}\) → 11

+ \(1101_{two}\) → 13

+ \(1001_{two}\) → 9

- \(111_{two}\) → 7

: 11 + 13 + 9 - 7 = 26

26 → \(11010_{two}\)

978.

Two similar cylindrical cans have heights of 7cm and 21cm, if the smaller holds 250g of sugar, how many kg of sugar will the larger one hold?

A.

0.75

B.

1.5

C.

2.25

D.

3.5

E.

6.75

Correct answer is E

- If two solids are similar, the ratio of their volumes is equal to the cube of the ratio of their corresponding sides.

Given: Heights of cylinder  -->     21 : 7 or  3 : 1 = \(\frac{3}{1}\) 

                                = 3 times height enlargement

            Volume / Capacity of larger cylinder = 3\(^3\) \(\times\) 250g 

                                = 27 \(\times\) 250g = 6,750 or 6.75kg

 

979.

If y varies inversely as x2, how does x vary with y?

A.

x varies inversely as y2

B.

x varies inversely as \(\sqrt{y}\)

C.

x varies directly as y2

D.

x varies directly as \(\sqrt{y}\)

E.

x varies directly as y

Correct answer is B

No explanation has been provided for this answer.

980.

The nth term of a sequence is given as \(4 \times 3^{(3 - n)}\). Calculate the third term.

A.

12

B.

32

C.

4

D.

3

E.

1

Correct answer is C

\(4 \times 3^{(3 - n)}\)

for the third term, n = 3

then 

\(4 \times 3^{(3 - 3)}\) = \(4 \times 3^{0}\) = 4 x 1 = 4.