How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
In the diagram, MN//PO, < PMN = 112o, < PNO = 129oo and < MPN = yo. Find the value of y
51o
54o
56o
68o
Correct answer is B
In \(\bigtriangleup\) NPO + PNO + PNO + < NOP = 180o(sum of interior angles of a \(\bigtriangleup\) )
i.e. NPO + 129 + 37 = 180
< NOP = 180 - (129 + 37) = 14o
< MNP = < NOP = 14o (alt. < s)
In \(\bigtriangleup\) MPN
< PMN + < MNP + y = 180(sum of interior angles of a \(\bigtriangleup\))
i.e. 112 + 14 + y = 180o
y = 180 - (112 + 14) = 180 - 126 = 54o
11.1
10.5
10.3
9.9
Correct answer is A
No explanation has been provided for this answer.
2
4
6
8
Correct answer is A
median = (\(\frac{N + 1}{2}\))th = (\(\frac{25 + 1}{2}\))th
= \(\frac{26th}{2}\)
= 13th
the 13th is 2
6.0
3.0
2.4
1.8
Correct answer is C
\(\begin{array}{c|c} x & f & fx\\ \hline 1 & 6 & 6 \\
2 & 8 & 16\\ 3 & 8 & 18\\ 4 & 5 & 20\end{array}\)
mean x = \(\frac{\sum fx}{\sum f}\)
= \(\frac{60}{25}\)
x = 2.4
10
24
25
30
Correct answer is C
6 + 8 + 6 + 5 = 25