How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
The length of a rectangle is 10 cm. If its perimeter is 28 cm, find the area
30cm\(^2\)
40cm\(^2\)
60cm\(^2\)
80cm\(^2\)
Correct answer is B
perimeter = 2( length + breadth)
→ 28 = 2 (10+ b)
14 - 10 = b
b = 4
Area = length x breadth
10 x 4 → 40cm\(^2\)
In the diagram, ∠ZWZY and WYX are right angles. Find the perimeter of WXYZ.
30cm
32cm
35cm
37cm
Correct answer is B
In ΔWYZ:
hyp\(^2\) = adj\(^2\) + opp\(^2\)
hyp\(^2\) =3\(^2\) + 4\(^2\) → 9 + 16
hyp\(^2\) = 25
hyp = 5
In ΔWXY:
hyp\(^2\) = adj\(^2\) + opp\(^2\)
hyp\(^2\) = 12\(^2\) + 5\(^2\) = 144 +25
hyp\(^2\) = 169
hyp = 13
the perimeter of WXYZ. = 3+4+12+13 → 32cm
126.5cm\(^2\)
165.0cm\(^2\)
212.0cm\(^2\)
214.5cm\(^2\)
Correct answer is D
The surface area of an open-top cylinder = πr(r + 2h),
where 'r' is the radius and 'h' is the height of the cylinder.
= \(\frac{22}{7}\) * 3.5 (3.5 + 2 * 8)
= 11 (3.5 + 16) → 11 (19.5)
= 214.5cm\(^2\)
3.611m
4.521m
4.792m
3.962m
Correct answer is C
Sin θ = \(\frac{opp}{hyp}\) → \(\frac{x}{6}\)
cross multiply:
sin53º * 6 = x
0.7986 * 6
4.792m
Find the area of the sector OPSQ
15.40cm\(^2\)
17.64cm\(^2\)
23.10cm\(^2\)
32.34cm\(^2\)
Correct answer is D
\(\frac{θ}{360}\) *π * r\(^2\) → \(\frac{210 * 22 * 4.2 * 4.2}{360 * 7}\)
\(\frac{1617}{50}\) = 32.34cm\(^2\)