How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
1cm
\(\sqrt{\frac{3\pi}{24}}\)
\(\frac{\pi}{24\sqrt{3}}\)
24\(\sqrt{3}\)
Correct answer is C
The rise of water is equivalent to the volume of the sphere of radius \(\frac{1}{2}\)cm immersed x \(\frac{1}{\text{No. of sides sq. root 3}}\)
Vol. of sphere of radius = 4\(\pi\) x \(\frac{1}{8}\) x \(\frac{1}{3}\) - (\(\frac{1}{2}\))3
= \(\frac{1}{8}\)
= \(\frac{\pi}{6}\) x \(\frac{1}{4\sqrt{3}}\)
= \(\frac{\pi}{24\sqrt{3}}\)
If sec\(^2\) \(\theta\) + tan\(^2\) \(\theta\) = 3, then the angle \(\theta\) is equal to
30o
45o
60o
90o
105o
Correct answer is B
sec\(^2\) \(\theta\) + tan\(^2\) \(\theta\) = 3
Where 1 + tan\(^2\) \(\theta\) = sec\(^2\) \(\theta\)
1 + tan\(^2\) \(\theta\) + tan\(^2\) \(\theta\) = 3
2 tan\(^2\) \(\theta\) = 2
tan\(^2\) \(\theta\) = 1
tan\(\theta\) = √1
where √1 = 1
tan\(\theta\) = 1
And tan 45° = 1
∴ \(\theta\) = 45°
1, 1.8 and 1.5
1.8, 1.5 and 1
1.8, 1 and 1.5
1.51, 1 and 1.8
1.5, 1.8 and 1
Correct answer is B
By re-arranging the goals in ascending order 0. 0. 0. 0. 0, 1. 1. 1. 1. 1. 1, 2, 2, 2, 2, 3, 3, 3, 4, 4, 5.
Mean = \(\frac{36}{20}\) = 1.8
Median = \(\frac{1 + 2}{2}\)
= \(\frac{3}{2}\)
= 1.5
Mode = 1
= 1.8, 1.5 and 1
A regular hexagon is constructed inside a circle of diameter 12cm. The area of the hexagon is
36\(\pi\)cm2
54\(\sqrt{3}\)cm2
\(\sqrt{3}\)cm2
\(\frac{1}{x - 1}\)
Correct answer is B
Sum of interior angle of hexagon = [2(6) - 4]90°
= 720°
sum of central angle = 360°
Each central angle = \(\frac{360}{6}\)
= 60°
Area of Hexagon = \(\frac{1}{2}\) x 6 x 6 sin 60°
\(\frac{36 \times 6\sqrt{3}}{2 \times 2}\)
= \(54 \sqrt{3}\)cm2
12cm
6cm
6\(\sqrt{2}\)cm
12\(\sqrt{2}\)cm
Correct answer is C
\(\frac{6}{\sin 30}\) = \(\frac{x}{\sin 135}\)
\(\frac{6}{\sin 30}\) = \(\frac{x}{\sin 45}\)
x = \(\frac{6 \times \sin 45}{\sin 30}\)
= \(6 \sqrt{2}\)cm