How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
Simplify 3 - 2 \(\div\) \(\frac{4}{5}\) + \(\frac{1}{2}\)
1\(\frac{3}{4}\)
-1
1\(\frac{3}{10}\)
1
1\(\frac{9}{10}\)
Correct answer is D
3 - 2 \(\div\) (\(\frac{4}{5}\)) + \(\frac{1}{2}\)
3 - (2 x \(\frac{5}{4}\)) + \(\frac{1}{2}\) = 3 - \(\frac{10}{4}\) + \(\frac{1}{2}\)
= 3 - \(\frac{5}{2}\) + \(\frac{1}{2}\)
= \(\frac{6 - 5 + 1}{2}\)
= \(\frac{2}{2}\)
= 1
Rationalize the expression \(\frac{1}{\sqrt{2} + \sqrt{5}}\)
\(\frac{1}{3}\)(\(\sqrt{5} - \sqrt{2}\)
\(\frac{\sqrt{2}}{3}\) + \(\frac{\sqrt{5}}{5}\)
\(\sqrt{2} - \sqrt{5}\)
5(\(\sqrt{2} - \sqrt{5}\)
\(\frac{1}{3}\)(\(\sqrt{2} - \sqrt{5}\)
Correct answer is A
\(\frac{1}{\sqrt{2} + \sqrt{5}}\)
\(\frac{1}{\sqrt{2} + \sqrt{5}} \times \frac{(\sqrt{2} - \sqrt{5})}{(\sqrt{2} - \sqrt{5})}\)
= \(\frac{\sqrt{2} - \sqrt{5}}{2 - 5}\)
= \(\frac{\sqrt{2} - \sqrt{5}}{-3}\)
= \(\frac{1}{3} (\sqrt{5} - \sqrt{2})\)
120km/hr
60km/hr
670km/hr
40km/hr
Correct answer is B
Speed = \(\frac{distance}{time}\)
let x represent the speed, d represent distance
x = \(\frac{d}{4}\)
d = 4x
2x = \(\frac{600 - d}{3}\)
6x = 600 - d
6x = 600 - 4x
10x = 600
x = \(\frac{600}{10}\)
= 60km/hr
Find the mean of the following 24.57, 25.63, 24.32, 26.01, 25.77
25.12
25.30
25.26
25.50
25.75
Correct answer is C
\(\frac{24.57 + 25.63 + 24.32 + 26.01 + 25.77}{5}\)
mean = \(\frac{126.3}{5}\)
= 25.26
P = 60o and R = 90o
P = 30o and R = 120o
P = 90o and R = 60o
P = 60o and R 60o
P = 45o and R = 105o
Correct answer is A
By using cosine formula, p2 = Q2 + R2 - 2QR cos p
Cos P = \(\frac{Q^2 + R^2 - p^2}{2 QR}\)
= \(\frac{(3)^2 + 2(\sqrt{3})^2 - 3^2}{2\sqrt{3}}\)
= \(\frac{3 + 12 - 9}{12}\)
= \(\frac{6}{12}\)
= \(\frac{1}{2}\)
= 0.5
Cos P = 0.5
p = cos-1 0.5 = 60°
= < P = 60°
If < P = 60° and < Q = 30
< R = 180° - 90°
angle P = 60° and angle R is 90°