How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
1.5
\(\frac{5}{2}\)
\(\frac{96}{48}\)
0.5
Correct answer is A
Numerator: 96 → 37.5% of 96 = 36
Decreased by 36 → 96 - 36
New numerator = 60
Denominator: 50 → 20% of 50 = 10
Decreased by 10 → 50 - 10 = 40
New Denominator = 40
New fraction = \(\frac{60}{40}\) or 1.5
The locus of points equidistant from a fixed point.
circle
perpendicular lines
straight line
bisector
Correct answer is A
Definition of a circle
3.0
4.5
3.5
2.5
Correct answer is C
where Log\(_2\) 8√2 → Log\(_2\) √128
→ Log\(_2\) 128\(^\frac{1}{2}\)
= \(\frac{1}{2}\) * (Log\(_2\) 128) → \(\frac{1}{2}\) * (Log\(_2\) 2\(^7\))
= 7 * \(\frac{1}{2}\) * (Log\(_2\) 2)
where (Log\(_2\) 2) = 1
→ 7 * \(\frac{1}{2}\) * 1
= \(\frac{7}{2}\) or 3.5
Find the determinant of the matrix A = \(\begin{pmatrix} 2 & 3 \\ 1 & 3 \end{pmatrix}\)
4
2
5
3
Correct answer is D
|A| = (2*3) - (1*3)
→ 6 - 3
= 3
Given that r = \( \sqrt \frac{3v}{\pi h} \), make v the subject of the formula
v = 3 \(πr^2\) h
v = \(\frac{πrh}{3}\)
v = \(\frac{πr^2h}{3}\)
v = 3πrh
Correct answer is C
square both sides to remove the big square root
→ r\(^2\) = \(\frac{3v}{πh}\)
cross multiply
3v = r\(^2\) * πh
v = \(\frac{πr^2h}{3}\)