How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
In the diagram, PQRS is a parallelogram and ∠QRT = 30o. Find x
95o
100o
120o
150o
Correct answer is D
Since ∠QRS = 180o - 30o = 150o and ∠SPQ = ∠QRS (theorem opp. angles in a parallelogram are equal) ∴ x = 150o
In the diagram PQ and MN are straight lines. Find the value of x
13o
17o
28o
30o
Correct answer is B
The straight line MN = 180 = 2(x+30o) + 86o =>
180 = 2x + 60o + 86o => 180o = 2x + 146o => 2x = 180 - 46 = 34o => x = 34/2 = 17o
\(\frac{1}{10}\)
\(\frac{3}{10}\)
\(\frac{9}{20}\)
\(\frac{11}{20}\)
Correct answer is A
Prob.(John pass)\(\frac{3}{4}\) prob.(John fail) \(=1-\frac{3}{4}=\frac{1}{4}\)
Prob.(James pass) \(\frac{3}{5}\) Prob.(James fail) \(=1-\frac{3}{5}=\frac{2}{5}\)
Prob(both boys fail)\(\frac{1}{4}\times \frac{2}{5}=\frac{1}{10}\)
2
3
4
5
Correct answer is B
\(x^2+(x-1)^2 = (\sqrt{13})^2 \Rightarrow x^2 + x^2 - 2x + 1 = 13\\
2x^2 - 2x - 12 = 0\) dividing through by 2
\(x^2 - x- 6 = 0; (x-3)(x-2) = 0 \Rightarrow x = 3 or -2 \)
Make f the subject of the relation \(v = u + ft\)
\(\frac{v-u}{t}\)
\(\frac{u-v}{t}\)
\(t(v+u\)
\(\frac{v}{u}-t\)
Correct answer is A
\(v=u+ft \Rightarrow v-u=ft\Rightarrow f=\frac{v-u}{t}\)