How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
45 years
72 years
108 years
216 years
Correct answer is C
Given that the ages are in the ratio 3: 4: 5.
Let the sum of their ages be t.
\(\therefore\) The youngest age = \(\frac{3}{12} t\)
The eldest age = \(\frac{5}{12} t\)
\(\implies \frac{5}{12} t - \frac{3}{12} t = 18\)
\(\frac{2t}{12} = 18 \implies t = \frac{18 \times 12}{2}\)
t = 108 years.
The sum of their ages = 108 years.
If \(104_x = 68\), find the value of x
5
7
8
9
Correct answer is C
\(104_x = 68\\
1 \times x^2 + 0 \times x + 4 \times x^0 = 68\\
x^2 = 68 - 4; x^2 = 64\\
x = \sqrt{64}=8\)
Which of the following numbers is perfect cube?
350
504
950
1728
Correct answer is D
No explanation has been provided for this answer.
Simplify \(\left(\frac{16}{81}\right)^{-\frac{3}{4}}\times \sqrt{\frac{100}{81}}\)
\(\frac{80}{243}\)
\(\frac{1}{64}\)
\(\frac{25}{6}\)
\(\frac{15}{4}\)
Correct answer is D
\(\left(\frac{16}{81}\right)^{-\frac{3}{4}}\times \sqrt{\frac{100}{81}}\\
\frac{1}{\left(\sqrt[4]{\frac{16}{81}}\right)^3}\times \frac{10}{9}=\frac{1}{\left(\frac{2}{3}\right)^3}\times\frac{10}{9}\\
=\frac{27}{8}\times \frac{10}{9}=\frac{15}{4}\)
\(\frac{1}{3}\)
\(\frac{1}{2}\)
\(1\frac{1}{6}\)
\(1\frac{1}{2}\)
Correct answer is D
\(2\frac{1}{6} + 2\frac{7}{12}\)
= \(\frac{13}{6} + \frac{31}{12}\)
= \(\frac{26 + 31}{12}\)
= \(\frac{57}{12} = \frac{19}{4}\)
\(\frac{19}{4} - 3\frac{1}{4}\)
= \(\frac{19}{4} - \frac{13}{4}\)
= \(\frac{6}{4}\)
= \(1\frac{1}{2}\)